代入演算子の実行順

mainもフレンド関数にできるのかー。

#include <iostream>
using namespace std;

int main();

class Foo {
private:
  int i;

public:
  Foo();
  Foo(int i);
  Foo &operator=(Foo &foo);
  friend int main();
};

Foo::Foo() : i(0) {}
Foo::Foo(int i) : i(i) {}

Foo &Foo::operator=(Foo &foo) {
  cout << "operator=:\t" << this << "<-" << &foo << "\n";
  i = foo.i;
  return *this;
}

int main() {
  Foo foo1, foo2, foo3(100);
  cout << "&foo1:\t\t" << &foo1 << "\n";
  cout << "&foo2:\t\t" << &foo2 << "\n";
  cout << "&foo3:\t\t" << &foo3 << "\n";

  foo1 = foo2 = foo3;

  cout << "foo1:\t\t" << foo1.i << "\n";
  cout << "foo2:\t\t" << foo2.i << "\n";
  cout << "foo3:\t\t" << foo3.i << "\n";

  return 0;
}

&foo1:          0x22cce4

&foo2:          0x22cce0

&foo3:          0x22ccdc

operator=:      0x22cce0<-0x22ccdc

operator=:      0x22cce4<-0x22cce0

foo1:           100

foo2:           100

foo3:           100